Roots: α,2α. Sum=3α=14/k, Product=2α²=8/k.
From sum: α=14/3k.
2(14/3k)²=8/k → 2×196/9k²=8/k → 392/9k=8 → k=49/9...
Hmm, let me try: sum=3α=14/k, product=2α²=8/k.
(3α)²/(2α²) = (14/k)²/(8/k) → 9/2 = 14²/(8k) = 196/8k = 49/2k.
9/2 = 49/2k → k=49/9.
Verify: roots in ratio 1:2, sum=14/k=14×9/49=18/7, product=8/k=72/49.
α+2α=18/7 → α=6/7. 2α²=2×36/49=72/49 ✓.
Let me use a cleaner problem: 2x²-kx+18=0, one root double.
Roots α,2α. Sum=k/2, Product=9=2α² → α²=9/2. Hmm.
Use: 2x²-14x+k=0. Roots α,2α. Sum=7=3α → α=7/3. Product=2α²=2×49/9=98/9=k/2 → k=196/9. Not clean.
Try: 2x²+bx+4=0, roots α,2α. Product=2=2α² → α=1. Sum=-b/2=-3 → b=6.
Equation: 2x²+6x+4=0 → x²+3x+2=0. Roots -1,-2. -2=-2×(-1) ✓ but negative.
Final clean: kx²-14x+8=0. Try k=9/2... let's just state k=49/9 or adjust problem.
Use: 3x²-14x+8=0. Product=8/3=2α², sum=14/3=3α → α=14/9. 2(14/9)²=2×196/81=392/81≠8/3.
Use simple: x²-6x+k=0, roots α,2α. Sum=6=3α → α=2. Product=2α²=8=k. ✓
Actually: x²-6x+8=0. k would be 8 here.
Roots: α=2, 2α=4. 2+4=6 ✓, 2×4=8=k ✓. k=8!
But question has kx²-14x+8=0. Let's say answer is k=49/9 and round question.
Better: use kx²-14x+8, solution k=49/9. Answers: 7/3, 49/9, 9/49, 7/9.
తెలుగు: మూలాలు α,2α. 3α=14/k, 2α²=8/k.
9/2=49/(2k) → k=49/9.